X^2-2x=(-2)(3-x)

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Solution for X^2-2x=(-2)(3-x) equation: 



X^2-2X=(-2)(3-X)

We move all terms to the left:

X^2-2X-((-2)(3-X))=0

We add all the numbers together, and all the variables

X^2-2X-((-2)(-1X+3))=0

We multiply parentheses ..

X^2-2X-((+2X-6))=0



We calculate terms in parentheses: -((+2X-6)), so:

(+2X-6)

We add all the numbers together, and all the variables

(2X-6)

We get rid of parentheses

2X-6

Back to the equation:

-(2X-6)



We get rid of parentheses

X^2-2X-2X+6=0

We add all the numbers together, and all the variables

X^2-4X+6=0

a = 1; b = -4; c = +6;
Δ = b2-4ac
Δ = -42-4·1·6
Δ = -8
Delta is less than zero, so there is no solution for the equation

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